Table of Contents
ConjugateTranspose
For an operator O, the method O.ConjugateTranspose() will change operator O to its conjugate transpose.
Example
We define: $$O=3.4+1.2a^{\dagger}_{0}\,a^{\phantom{\dagger}}_{0}+(2.5+I)a^{\dagger}_{1}\,a^{\phantom{\dagger}}_{2},$$ its conjugate transpose, $O^{\dagger}$ is equal to: $$O^{\dagger}=3.4+1.2a^{\dagger}_{0}\,a^{\phantom{\dagger}}_{0}+(2.5-I)a^{\dagger}_{2}\,a^{\phantom{\dagger}}_{1}.$$
Input
- Example.Quanty
NF=3 NB=0 O = NewOperator(NF,NB,{{3.4},{0,-0,1.2},{1,-2,2.5+I}}) print(O) O.ConjugateTranspose() print(O)
Result
Operator: Operator QComplex = 2 (Real==0 or Complex==1 or Mixed==2) MaxLength = 2 (largest number of product of lader operators) NFermionic modes = 3 (Number of fermionic modes (site, spin, orbital, ...) in the one particle basis) NBosonic modes = 0 (Number of bosonic modes (phonon modes, ...) in the one particle basis) Operator of Length 0 QComplex = 0 (Real==0 or Complex==1) N = 1 (number of operators of length 0) | 3.400000000000000E+00 Operator of Length 2 QComplex = 1 (Real==0 or Complex==1) N = 2 (number of operators of length 2) C 0 A 0 | 1.200000000000000E+00 0.000000000000000E+00 C 1 A 2 | 2.500000000000000E+00 1.000000000000000E+00 Operator: Operator QComplex = 2 (Real==0 or Complex==1 or Mixed==2) MaxLength = 2 (largest number of product of lader operators) NFermionic modes = 3 (Number of fermionic modes (site, spin, orbital, ...) in the one particle basis) NBosonic modes = 0 (Number of bosonic modes (phonon modes, ...) in the one particle basis) Operator of Length 0 QComplex = 0 (Real==0 or Complex==1) N = 1 (number of operators of length 0) | 3.400000000000000E+00 Operator of Length 2 QComplex = 1 (Real==0 or Complex==1) N = 2 (number of operators of length 2) C 0 A 0 | 1.200000000000000E+00 -0.000000000000000E+00 C 2 A 1 | 2.500000000000000E+00 -1.000000000000000E+00
